In fig 10.11 if tp and tq
WebIn Fig. 10.11 , if TP and TQ are the two tangents to a circle with centre O so that ∠POQ=110 ∘ . then ∠PTQ is equal to (A)60 ∘ (C) 80 ∘ B) 70 ∘ (D)90 Fig. 10.1 Solution Verified by Toppr … WebIn Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that ∠ POQ = 110°, then ∠ PTQ is equal to (A) 60° (B) 70° (C) 80° (D) 90° Fig. 10.11 296 Views Switch Flag Bookmark Advertisement From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm. The radius of the circle is
In fig 10.11 if tp and tq
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WebDec 27, 2016 · 1. The mean is calculated using: (9.4 + 17 + 7.3 + 7 + 16.1 + 5.4 + 5.9 + 8.5 + 4.2 + 9.2)/ 10 = 9 2. The standard deviation is 4.31 3. The years are 1996, 1997, 1999-200 WebFeb 8, 2024 · In Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that ∠POQ=110∘, then ∠PTQ is equal to (A) 60∘ (B) 70∘ (C. The world’s only live instant tutoring platform. Become a tutor About us Student login Tutor login. Login. Student Tutor. Filo instant Ask button for chrome browser. ...
WebJan 14, 2024 · In Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that ∠POQ=110∘, then ∠PTQ is equal to 60∘ 70∘ 80∘ 90∘ Viewed by: 0 students Updated on: Jan 14, 2024 2 students asked the same question on Filo Learn from their 1-to-1 discussion with Filo tutors. Still did not understand this question? WebSep 15, 2024 · 4611 W Fig St Unit 210, Tampa, FL 33609-1947 is currently not for sale. The 938 sq. ft. condo is a 2 bed, 2.0 bath unit. This condo was built in 1968 and last sold on …
WebIn Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that ∠ POQ = 110°, then ∠ PTQ is equal toa)60°b)70°c)90°d)noneCorrect answer is option 'B'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. WebMar 22, 2024 · In Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that ∠ POQ = 110°, then ∠ PTQ is equal to In the above figure, OPTQ is a quadrilateral and ∠P and ∠Q are 90° The sum of the interior angles of a quadrilateral is 360°. Therefore, in OPTQ, ∠Q + ∠P + ∠POQ + ∠PTQ = 360° 90° + 90° + 110° + ∠PTQ = 360° 290° + ∠PTQ = 360°
WebIn Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that POQ = , then PTQ is equal to (A) (B) (C) (D) Answers (1) The correct option is (b) In figure, Since POQT …
WebAnswer of In Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O . Answer of In Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O . Login/Register. PW Centres PW Skills Ask Doubt. All Courses . IIT JEE. CLASS 11; CLASS 12; Dropper; NEET. CLASS 11; CLASS 12; Dropper; UPSC; UPSC OFFLINE; GATE. Civil ; daylight savings time in americaWebIn Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that ∠ POQ = 110°, then ∠ PTQ is equal to (A) 60° (B) 70° (C) 80° (D) 90° Answer Popular Questions of Class 10 Mathematics Q:- Find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively. Q:- daylight savings time in arizonaWebContents. 1 In Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that ∠ POQ = 110°, then ∠ PTQ is equal to (A) 60° (B) 70° (C) 80° (D) 90° ; 2 In Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that ∠ POQ = 110°, then ∠ PTQ is equal to (A) 60° (B) 70° (C) 80° (D) 90°. 2.1 In Fig. 10.11, if TP and TQ are the two … daylight savings time in australia 2021WebSolutions for In Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that ∠ POQ = 110°, then ∠ PTQ is equal toa)60°b)70°c)90°d)noneCorrect answer is option 'B'. … daylight savings time in australia 2020WebFinal answer. 10.11 Using nodal analysis, find i, (t) in the circuit in # Fig. 10.60. ML 0.25 F 2 H 2Ω 1 H 8 sin (2t + 30°) V (± 0.5 F cos 2t A. daylight savings time in austriaWebOct 27, 2024 · In Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that Z POQ = 110°, then Z PTQ is equal to (A) 60° (B) 700 (C) 80° (D) 90° See answers Advertisement priyanshi310sharma Answer: 70° Step-by-step explanation: because the quad. formed by centre, point of contact of two tamgents and ext pt. is a cyclic quad daylight savings time in atlantaWebIn Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that ∠ POQ = 110°, then ∠ PTQ is equal to (A) 60° (B) 70° (C) 80° (D) 90° Fig. 10.11 daylight savings time in california